1class Solution:
2 def isPalindrome(self, s: str) -> bool:
3 s = [char for char in s.lower() if char in string.ascii_lowercase or char in string.digits]
4 for i in range(0, len(s)//2):
5 if s[i] != s[-i-1]:
6 return False
7 return True
This is a class Solution with a method isPalindrome that takes a string s as input and returns a boolean value indicating whether or not the input string s is a palindrome. The method first converts the input string s to a list s by iterating through each character in s with the help of a for loop with a list comprehension inside. The characters are converted to lowercase and only alphanumeric characters (lowercase letters and digits) are included in the list s with the help of the string.ascii_lowercase and string.digits constants. Then, the method uses a for loop that iterates through the first half of the list s, comparing each pair of characters from the opposite ends of the list. If the characters are not equal, the method returns False indicating that the input string is not a palindrome. Otherwise, if all pairs of characters are equal, the method returns True indicating that the input string is a palindrome.
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